Regex to get everything between first and last double quote but without double quote -


i have following data

"full name":"vg","address":"abc, 128, street no 9,"(0112093-0)"" 

now clear in "key":"value" format , separated comma.so have 2 keys "full name" , "address" . need write regex sting between double quotes ,

full name : vg address : abc, 128, street no 9,"(0112093-0)" 

i tried following getting double quotes along

"(\w+)":"(.*?)" 

i want remove fist , last double quotes both key , value.

you can use /\"(\w+)":"(.*?)"(?=,|$)/g. test online

i have assumed value can terminate ", (might boundary case) or "$.


Comments

Popular posts from this blog

What is happening when Matlab is starting a "parallel pool"? -

angular - DownloadURL return null in below code -

php - Cannot override Laravel Spark authentication with own implementation -