regex - Compare fields in line against each other -


i have file per below;

             env_ab 1.1.11.0              env_bb 1.1.11.0              env_cc 1.1.11.0              env_dd 1.1.11.0              env_ff 1.1.11.0              env_gg 1.1.11.0              env1_ab 1.1.11.0              env1_bb 1.1.10.0              env1_cc 1.1.11.0              env1_dd 1.1.11.0              env1_ff 1.1.11.0              env1_gg 1.1.11.0

- can seen, each env there 6 version numbers. - want do, compare 6 version number each env. - so, env_(ab,bb,cc..etc) has 6 versions (1.1.11.0), want able compare env_ab,bb,cc,dd,ff,gg 1 , if same print 1 env , version. if not same, print out not same & print once env same version.

expected output above if envs file same;

          env_ab 1.1.11.0           env1_ab 1.1.11.0

however there diffrenet version in 1 of env (so change env_bb version 1.1.10.0), expected output be; env_ab 1.1.11.0 env_bb 1.1.10.0 env1_ab 1.1.11.0 feasible? have researched associative arrays not seem resolution this.

if understand trying do, this:

  1. take file pattern of key_dk version defines group , dk ignored
  2. print first line , line of group.

in awk can do:

$ awk '{split($1, x, "_")          if (a[x[1], $2]) next          a[x[1], $2]=$1 ofs $2 }         end{ (i in a) print a[i]}' file env1_ab 1.1.11.0 env_ab 1.1.11.0 env1_bb 1.1.10.0

the order printed not same file order since associative arrays unordered in awk. if want output same file order, loop through file twice.


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