java - Unable to extract out name in 4 level deep nested JSON array -


i trying create android app shows details restaurants. have parsejson function takes string json argument. trying show name of individual restaurants in json below. able extract individual restaurant(3 levels deep) , print them out through log.d console not able extract out individual restaurant's name. here code

public void parsejson(string jsonquery){         //parsing json         try {             jsonobject jsonobject = new jsonobject(jsonquery);             if (jsonobject != null){                 jsonarray restaurants = jsonobject.getjsonarray("restaurants");                 (int = 0; < restaurants.length(); i++){                     jsonobject restaurant = restaurants.getjsonobject(i);                     if (restaurant != null){                         string tempname = restaurant.getstring("name");                         log.d(tag, "restaurant name: " + tempname);                     }                 }             }          } catch (jsonexception e) {             log.d(tag, "exception catched: " + e);             e.printstacktrace();         }     }

here json file.

{   "results_found": 1281966,   "results_start": 0,   "results_shown": 2,   "restaurants": [     {       "restaurant": {         "r": {           "res_id": 16607974         },         "apikey": "123456789",         "id": "16607974",         "name": "bassine specialty cheese",         "url": "https://www.zomato.com/bass-vic/bassine-specialty-cheese-bass?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1",         "location": {           "address": "2125 bass hwy",           "locality": "bass",           "city": "bass",           "city_id": 1341,           "latitude": "-38.4833750000",           "longitude": "145.4670320000",           "zipcode": "3995",           "country_id": 14,           "locality_verbose": "bass, bass"         },         "switch_to_order_menu": 0,         "cuisines": "ice cream",         "average_cost_for_two": 7,         "price_range": 1,         "currency": "$",         "offers": [],         "thumb": "",         "user_rating": {           "aggregate_rating": "2.9",           "rating_text": "average",           "rating_color": "ffba00",           "votes": "5"         },         "photos_url": "https://www.zomato.com/bass-vic/bassine-specialty-cheese-bass/photos?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1#tabtop",         "menu_url": "https://www.zomato.com/bass-vic/bassine-specialty-cheese-bass/menu?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1&openswipebox=menu&showminimal=1#tabtop",         "featured_image": "",         "has_online_delivery": 0,         "is_delivering_now": 0,         "deeplink": "zomato://restaurant/16607974",         "has_table_booking": 0,         "events_url": "https://www.zomato.com/bass-vic/bassine-specialty-cheese-bass/events#tabtop?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1",         "establishment_types": []       }     },     {       "restaurant": {         "r": {           "res_id": 17649424         },         "apikey": "3d93604b4a84d85f374f39ea3b644132",         "id": "17649424",         "name": "schobels' restaurant",         "url": "https://www.zomato.com/columbus-tx/schobels-restaurant-columbus?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1",         "location": {           "address": "2020 milam st 78934",           "locality": "columbus",           "city": "columbus",           "city_id": 9241,           "latitude": "29.6965000000",           "longitude": "-96.5405000000",           "zipcode": "78934",           "country_id": 216,           "locality_verbose": "columbus, columbus"         },         "switch_to_order_menu": 0,         "cuisines": "german, southern",         "average_cost_for_two": 25,         "price_range": 2,         "currency": "$",         "offers": [],         "thumb": "",         "user_rating": {           "aggregate_rating": "4.0",           "rating_text": "very good",           "rating_color": "5ba829",           "votes": "164"         },         "photos_url": "https://www.zomato.com/columbus-tx/schobels-restaurant-columbus/photos?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1#tabtop",         "menu_url": "https://www.zomato.com/columbus-tx/schobels-restaurant-columbus/menu?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1&openswipebox=menu&showminimal=1#tabtop",         "featured_image": "",         "has_online_delivery": 0,         "is_delivering_now": 0,         "deeplink": "zomato://restaurant/17649424",         "has_table_booking": 0,         "events_url": "https://www.zomato.com/columbus-tx/schobels-restaurant-columbus/events#tabtop?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1",         "establishment_types": []       }     }   ] }

error getting: org.json.jsonexception: no value name

your jsonquery contain jsonobject inside jsonobject named restaurant need jsonobject jsonobject restaurant = restaurants.getjsonobject(i);

like jsonobject restaurantsjsonobject =restaurant.getjsonobject("restaurant");

try below example name object

try {     jsonobject jsonobject = new jsonobject(jsonquery);     if (jsonobject != null){         jsonarray restaurants = jsonobject.getjsonarray("restaurants");         (int = 0; < restaurants.length(); i++){             jsonobject restaurant = restaurants.getjsonobject(i);             jsonobject restaurantsjsonobject =restaurant.getjsonobject("restaurant");             if(restaurantsjsonobject.has("name")) {                 string tempname = restaurantsjsonobject.getstring("name");                 log.d(tag, "restaurant name: " + tempname);             }         }     } } catch (jsonexception e) {     log.d(tag, "exception catched: " + e);     e.printstacktrace(); }

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