javascript - Why doesn't my arrow function return a value? -


i have arrow function looks (simplified):

const f = arg => { arg.touppercase(); };

but when call it, undefined:

console.log(f("testing")); // undefined

why?

example:

const f = arg => { arg.touppercase(); };  console.log(f("testing"));

(note: meant clean, canonical dupetarget specific issue arrow functions above.)

when use function body version of arrow function (with {}), there no implied return. have specify it. when use concise body (no {}), result of body expression implicitly returned function.

so write either explicit return:

const f = arg => { return arg.touppercase(); }; // explicit return ^^^^^^

or concise body:

const f = arg => arg.touppercase();

examples:

const f1 = arg => { return arg.touppercase(); };  console.log(f1("testing"));    const f2 = arg => arg.touppercase();  console.log(f2("testing"));

slightly tangential, speaking of {}: if want concise arrow's body expression object initializer, put in ():

const f = arg => ({prop: arg.touppercase()});

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