php - I require assistance with a SQL syntax error -


i writing code register , login system, , when testing receiving errors, there one:

"you have error in sql syntax; check manual corresponds mariadb server version right syntax use near 'where username = ''' @ line 1"

could please tell me means , solve it. here code in update-profile.php

<?php session_start(); ini_set("display_errors",1); $temp=$_session['username']; if(isset($_post)){     require 'database1.php';     $destination = 'background-images';     if(!isset($_files['backgroundimagefile']) || !is_uploaded_file($_files['backgroundimagefile']['tmp_name'])){         $backgroundnewimagename= 'background.jpg';         move_uploaded_file($_files['backgroundimagefile']['tmp_name'], "$destination/$backgroundnewimagename");     }     else{         $randomnum = rand(0, 9999999999);         $imagename = str_replace(' ','-',strtolower($_files['backgroundimagefile']['name']));         $imagetype = $_files['backgroundimagefile']['type'];         $imageext = substr($imagename, strrpos($imagename, '.'));         $imageext = str_replace('.','',$imageext);         $imagename      = preg_replace("/\.[^.\s]{3,4}$/", "", $imagename);         $backgroundnewimagename = $imagename.'-'.$randomnum.'.'.$imageext;         move_uploaded_file($_files['backgroundimagefile']['tmp_name'], "$destination/$backgroundnewimagename");     }     $sql1="update users set backgroundpicture='$backgroundnewimagename' username = '$temp'";     $sql2="insert users (backgroundpicture) values ('$backgroundnewimagename') username = '$temp'";     $result = mysqli_query($database,"select * users username = '$temp'");     if( mysqli_num_rows($result) > 0) {         if(!empty($_files['backgroundimagefile']['name'])){             mysqli_query($database,$sql1)or die(mysqli_error($database));             header("edit-profile.php?username=$temp");         }     }      else {         mysqli_query($database,$sql2)or die(mysqli_error($database));         header("edit-profile.php?username=$temp");     }     $destination = 'avatars';     if(!isset($_files['imagefile']) || !is_uploaded_file($_files['imagefile']['tmp_name'])){         $newimagename= 'default.png';         move_uploaded_file($_files['imagefile']['tmp_name'], "$destination/$newimagename");     }     else{         $randomnum   = rand(0, 9999999999);         $imagename = str_replace(' ','-',strtolower($_files['imagefile']['name']));         $imagetype = $_files['imagefile']['type'];         $imageext = substr($imagename, strrpos($imagename, '.'));         $imageext = str_replace('.','',$imageext);         $imagename = preg_replace("/\.[^.\s]{3,4}$/", "", $imagename);         $newimagename = $imagename.'-'.$randomnum.'.'.$imageext;         move_uploaded_file($_files['imagefile']['tmp_name'], "$destination/$newimagename");     }     $sql5="update users set avatar='$newimagename' username = '$temp'";     $sql6="insert users (avatar) values ('$newimagename') username = '$temp'";     $result = mysqli_query($database,"select * users username = '$temp'");     if( mysqli_num_rows($result) > 0) {         if(!empty($_files['imagefile']['name'])){             mysqli_query($database,$sql5)or die(mysqli_error($database));             header("location:edit-profile.php?username=$temp");         }     }      else {         mysqli_query($database,$sql6)or die(mysqli_error($database));         header("location:edit-profile.php?username=$temp");     }       $user_firstname=$_request['firstname'];     $user_lastname=$_request['lastname'];     $user_email=$_request['email'];     $user_password=$_request['password'];     $user_shortbio=$_request['bio'];        $user_dob=$_request['dob'];     $user_gender=$_request['gender'];     $sql3="update user sets firstname='$firstname',lastname='$lastname',email='$email',password='$password',bio='$bio',dob='$dob',gender='$gender', username = '$temp'";         mysqli_query($database,$sql3)or die(mysqli_error($database));         header("edit-profile.php?username=$temp&request=profile-update&status=success"); }

in insert syntax, have used where

$sql6="insert users (avatar) values ('$newimagename') username = '$temp'";

should 

$sql6="insert users (avatar) values ('$newimagename')"; $sql2="insert users (backgroundpicture) values ('$backgroundnewimagename')";

also 

 $sql3="update user sets firstname='$firstname',lastname='$lastname',email='$email',password='$password',bio='$bio',dob='$dob',gender='$gender', username = '$temp'";

should below, remove , before where

$sql3="update user set firstname='$firstname',lastname='$lastname',email='$email',password='$password',bio='$bio',dob='$dob',gender='$gender' username = '$temp'";

and suggest read basic document


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