Count occurrence of a list in a List of Lists in Python -


i have list looks this:

co_list = [[387, 875, 125, 822], [397, 994, 135, 941], [397, 994, 135, 941], [397, 994, 135, 941], [397, 994, 135, 941], [1766, 696, 1504, 643]. . . ]

i need count number of identical co-ordinates lists , return count, 4 in case.

so far have tried:

def most_common(lst):     lst = list(lst)     return max(set(lst), key=lst.count)  each in kk :     print most_common(each)

using occurring element in each list. intention list if it's occurrence more 3.

expected output:

(element, count) = ([397, 994, 135, 941], 4)

any appreciated. thanks.

you can use collections.counter task:

from collections import counter  co_list = [[387, 875, 125, 822], [397, 994, 135, 941], [397, 994, 135, 941], [397, 994, 135, 941], [397, 994, 135, 941], [1766, 696, 1504, 643]]  common_list, appearances = counter([tuple(x) x in co_list]).most_common(1)[0]  # note 1 if appearances > 3:     print((list(common_list), appearances))  # ([397, 994, 135, 941], 4) else:     print('no list appears more 3 times!')

1) inner lists converted tuples because counter builds dict , lists being not hashable cannot used keys.


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