php - I am trying to update the data base table -


this update.php file fetching id username email , mobile number. here in same file trying update mysql table. press update button nothing happening. following update.php

    <?php      include ('config/config.php');       $id = $_get['id'];     if(isset($_get['id']))    {    $sql = "select username, email, mobile users id=".$id."";   $res= mysqli_query($conn, $sql);     $row=mysqli_fetch_array($res);    $username    = $row['username'];     $email       = $row['email'];    $mobile  = $row['mobile'];     }    if (isset($_post['update']))    {         $username = $_post['username'];         $email = $_post['email'];         $mobile = $_post['mobile'];          $upd = "update `users` set `username`='$username',`email`='$email',`mobile`='$mobile' id=$id";         $rest= mysqli_query($conn, $upd);          if ($rest) {             echo "data update successfully";         } else {             echo "failed update";         }         }         ?>

and html file. using post method 

        <form action="update.php" method="post">         <input type="hidden" name="id" id="id">         <input type="text"   name="username" id="username"       placeholder="username"          value="<?php echo $username;?>" ><br><br>         <input type="email"  name="email"      id="email"        placeholder="email"            value="<?php echo $email;?>"> <br><br>         <input type="mobile" name="mobilemobile "   id="mobile"  placeholder="mobile number"    value="<?php echo $mobile;?>" ><br><br>     </form>         <input type="submit" name="update" value="update" id="submit_update">

your form not have update parameter/element. below if block never successful.

if (isset($_post['update']))

edit: per edited code, submit button out of form element. value never submitted form. move submit button code inside form.

p.s. hope code testing purpose only, contains no input sanitization etc.


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