c# - Dividing with rest 0 -


i have question. have 2 numbers example:

81 / 9 or 25 / 5 or 12 / 6 , on..... these 2 numbers appear randomly. 

public simplespritesequence[] leftnumbers; public simplespritesequence rightnumbers; public simplespritesequence numberresul; randomizer numbersequence = new randomizer(1, 9);     public void getnumbers() {     if (!numbersequence.randomrule.hasnumbersleft())     {         numbersequence.randomrule.reset();     }     int firstnumberindex = numbersequence.getrandom();     leftnumbers[0].setcurrentspriteindex(firstnumberindex);     if (!numbersequence.randomrule.hasnumbersleft())     {         numbersequence.randomrule.reset();     }     int secondnumberindex = numbersequence.getrandom();     leftnumbers[1].setcurrentspriteindex(secondnumberindex);     if (!numbersequence.randomrule.hasnumbersleft())     {         numbersequence.randomrule.reset();     }     int rightnumberindex = numbersequence.getrandom();     rightnumbers.setcurrentspriteindex(rightnumberindex);      int findex = 10 * (int)leftnumbers[0].currentspriteindex;     int sindex = (int)leftnumbers[1].currentspriteindex;     int number = findex + sindex;     int lindex = (int)rightnumbers.currentspriteindex;     result = number / lindex;     debug.log(number + ":" + lindex + "=" + (math.truncate(result)));    while(math.truncate(result) >= 10)   {       if (!numbersequence.randomrule.hasnumbersleft())       {           numbersequence.randomrule.reset();       }       firstnumberindex = numbersequence.getrandom();      leftnumbers[0].setcurrentspriteindex(firstnumberindex);       if (!numbersequence.randomrule.hasnumbersleft())       {           numbersequence.randomrule.reset();       }       secondnumberindex = numbersequence.getrandom();         leftnumbers[1].setcurrentspriteindex(secondnumberindex);         if (!numbersequence.randomrule.hasnumbersleft())       {           numbersequence.randomrule.reset();       }       rightnumberindex = numbersequence.getrandom();         rightnumbers.setcurrentspriteindex(rightnumberindex);          findex = 10 * (int)leftnumbers[0].currentspriteindex;       sindex = (int)leftnumbers[1].currentspriteindex;       number = findex + sindex;       lindex = (int)rightnumbers.currentspriteindex;       result = number / lindex;   }}

with code operations these: 13:6 = 2 or 24:7 = 3 , on. how operations rest 0? example: 81 : 9 or 24 : 8 or 12 : 6 , on. how put condition?

you should use modulo operator uses % operator-symbol. returns remainder of division, instead of result.

12 % 6 = 0 21 % 3 = 0 21 % 6 = 3

it's nice identify odd , numbers.

further reading on msdn


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