python - How can I return raw_input to use under a different name? -


i'm trying create get_input() function can choose how input retrieved. 

def get_input(input_msg = '', getparam = 0, style = 'raw'):     if style.lower() 'arcpy':         return arcpy.getparameterastext(getparam)     if style.lower() 'raw':         return raw_input(input_msg)

however when used method got none no matter input parameter was. think because method imported main program doesn't have access parameters.

then tried

def get_input(style = 'raw'):     if style.lower() 'arcpy':         return arcpy.getparameterastext     if style.lower() 'raw':         return raw_input

wanting return function use elsewhere , simplify inputs function, got error

typeerror: 'nonetype' object not callable

for both settings of method. get_input() seems can return nonetype object in configuration.

how can fix able call raw_input() or arcpy.getparameterastext under different name?

the problem in if statements. is should never used comparison. editing code 

def get_input(style = 'raw'):     if style.lower() == 'raw':         return raw_input     if style.lower() == 'arcpy':         return arcpy.getparameterastext     raise ioerror("invalid input in 'style': {}".format(style))

fixed problem.


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