awk not printing variables as expected -


trying hard awk print out following variables. no matter how tried,

awk -f, -v x=$client_id -v y=$branch -v z=$uuid -v b=$hermes_group_csv_id 'begin {     ofs = ","; ors = "\n"     } {         if (length($3) == 0) {             printf "\nclient $x @ $y linux system time: $z pacific time: $b #####: column 3, row "; printf nr; printf " data missing in client $x group input csv. please check\n"         }      }' ${input_file}

it prints out

client $x @ $y linux system time: $z pacific time: $b #####: column 3, row 249 data missing in client $x group input csv. please check

could guru enlighten? thanks.

you using $x variable reference, $ in awk reference fields in input. variables used without decoration, x. so:

awk -f, -v x=$client_id -v y=$branch -v z=$uuid -v b=$hermes_group_csv_id 'begin {     ofs = ","; ors = "\n"     } {         if (length($3) == 0) {             print "\nclient "x" @ "y" linux system time: "z" pacific time: "b" #####: column 3, row "; printf nr; printf " data missing in client "x" group input csv. please check\n"         }     }' ${input_file}

it looks x quoted here, not: point have x appear not in quoted string, can expanded variable.


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