debugging - Pattern Printing-Where am I going wrong in this C++ code? -


i wrote program print n x n square pattern alternate 0's , 1's. eg. 5 x 5 square looks this:

enter image description here

i used following code-

#include<iostream.h> int main() {   int i, n;   cin >> n; //number of rows (and columns) in n x n matrix   for(i = 1; <= n*n; i++)   {     cout << " " << i%2;     if(i%n == 0)     cout << "\n";   }    fflush(stdin);   getchar();   return 0; }

this code works fine odd numbers numbers prints same thing in each new line , not alternate pattern.for 4 prints this-

enter image description here

where going wrong?

in opinion best way iterate on matrix using loop in loop.

i think code helpful you:

for(i = 0; < n; i++) {     (j = 1; j <= n; j++) {         cout<<" "<< (j + i) % 2;     }     cout<<"\n"; }

where n number of rows, i , j ints.

try understand why , how works.


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