Returning the last element of a list in haskell using recursion -


how last element in list in haskell? have written of code below: 

lastlist :: list -> lastlist lst =    case lst of        cons x xs -> lastlist xs        cons _ xs -> lastlist xs        empty    -> error "lastlist of empty list"

how do without using of built in functions?

you have check when element cons empty:

lastlist :: list -> lastlist lst =    case lst of        cons x empty -> x        cons _ xs    -> lastlist xs        empty        -> error "lastlist of empty list"

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